(X)^2+x=99

Solution for (X)^2+x=99 equation:

(X)^2+X=99

We move all terms to the left:

(X)^2+X-(99)=0

a = 1; b = 1; c = -99;
Δ = b2-4ac
Δ = 12-4·1·(-99)
Δ = 397
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{397}}{2*1}=\frac{-1-\sqrt{397}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{397}}{2*1}=\frac{-1+\sqrt{397}}{2}
$